InterviewSolution
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InterviewSolution
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A point moves in the plane `y` according to the law `x = A sin omegat, y = B cos omegat`, where`A,B & omega` are positive constant. The velocity of particle is given byA. `v = sqrt(A^(2) +B^(2)) omega`B. `v = sqrt(A^(2)cos^(2) omegat +B^(2) sin^(2) omegat)omega`C. `v = omega sqrt((A^(2)+B^(2))-(x^(2)+y^(2)))`D. `v = omega sqrt((A+B)^(2)-(x+y)^(2))` |
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Answer» Correct Answer - B `v_(x) = (dx)/(dt),v_(y) = (dy)/(dt) = v = sqrt(v_(x)^(2) +v_(y)^(2))` |
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