InterviewSolution
Saved Bookmarks
| 1. |
A point moves with uniform acceleration and `v_(1), v_(2)`, and `v_(3)` denote the average velocities in the three successive intervals of time `t_(1).t_(2)`, and `t_(3)` Which of the following Relations is correct?.A. `(v_(1)-v_(2)):(v_(2)-v_(3)=(t_(1)-t_(2):(t_(2)+t_(3)`.B. `(v_(1)-v_(2)):(v_(2)-v_(3)=(t_(2)-t_(2):(t_(2)+t_(3)`C. `(v_(1)-v_(2)):(v_(2)-v_(3)=(t_(1)-t_(2):(t_(2)+t_(3)`D. `(v_(1)-v_(2)):(v_(2)-v_(3)=(t_(1)-t_(2):(t_(2)+t_(3)` |
|
Answer» Correct Answer - B Suppose `u` be the initial velocity. Velocity after time `t_(1)`: `v_(11) =u+at_(1)` Velocity after time `t_(1) +t_(2)`: `v_(22) =u +a (t_(1) +t_(2)` Velocity after time `t_(1) +t_(2) +t_(3)`: `v 3 =u+a (t_(1) +t_(2) +t_(3))` Now `v_(1) =(u+v_(11))/(2) =(u+u+at_(1))/(2) =u+(1)/(2) at_(1)` `v_(2) =(v_(11) +v_(22))/(2) =u+at_(1) +(1)/(2_(2))` `v_(3) =(v_(33)+ v_(33))/(2) =u+at_(2) + (1)/(2) at_(3)` So `v_(1)-v_(2) =- (1)/(2) a(t_(1) +t_(2))` `v_(2)-v_(3) =-(1)/(2) a(t_(2)-t_(3))` `(v_(1)-v_(2))`: `(v_(2)-v_(3) =(t_(1) +t_(2))` : `(t_(2) +t_(3))`. |
|