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A potential difference of 3V is applied across a conductor of resistance `1.5 Omega`. Calculate the number of electrons flowing through it in one second. Given charge on electron, `e=1.6 xx10^(-19)C`.

Answer» Here, `V=3 "volt" , R=1.5 Omega`,
`e=1.6 xx10^(-19)C, t=1s`.
Now, `I=V/R=3/1.5=2A` and `I=Q/t= ("ne")/(t)`
or `n= It/e =2xx1/1.6xx10^(-19)=1.25xx10^(19)`


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