InterviewSolution
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InterviewSolution
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A proton and alpha particle are accelerated through the same accelerating potential. Which one of the two has (a) greater value of de-broglie wavelength associated with it, and (b) less kinetic energy? justify your answer. |
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Answer» (a) De-Broglie wavelenth of a particle depends upon its mass and chargbe for same accelerating potential, such that `lambda prop (1)/(sqrt("mass"xx "charge")` Mass and charge of a deuteron are `2m_(rho)and e` respectively and mass and charge of an alpha particle are `4m^(rho)` and 2e respectively. Where, `m_(rho)` is the mass of a proton and e is the charge of an electron. `(lambda_(d))/(lambda_(prop))=(sqrt(4mp.2e))/(sqrt(2mp.e))=2` `rArr" "lambda_(d)=2lambda_(prop)`. |
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