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A proton is accelerated to 1/10th of the velocity of light. If its velocity can be measured with a precision of +- 0.5%, what must be its uncertanity in position?

Answer» <html><body><p></p>Solution :Velocity of <a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a> `= 3 xx 10^(8) ms^(-1)` <br/> `:.` Velocity of proton `= (1)/(10) xx 3 xx 10^(8) = 3 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>) ms^(-1)` <br/> `Delta v = (0.5)/(100) xx 3 xx 10^(7) = 1.5 xx 10^(5) ms^(-1)` <br/> Applying Heisenberg's uncertanity principle. <br/> `Delta x. m Delta v = (h)/(4pi)` <br/> We get `Delta x = (h)/(4pi xx m Delta v) = (6.626 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/34-308171" style="font-weight:bold;" target="_blank" title="Click to know more about 34">34</a>) kg m^(2) s^(-1))/(4 xx 31.43 xx 1.66 xx 10^(-27) kg xx 1.5 xx 10^(5) ms^(-1)) = 2.11 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a>) m`</body></html>


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