A proton (or charged particle) moving with velocity `v` is acted upon by electric field `E` and magnetic field `B`. The proton will move underflected ifA. E is perpenducular to BB. E is parallel to v and perpendicular to BC. E,B and v are mutually perpendicular and v=E/BD. E and B both are parallel to v

A proton (or charged particle) moving with velocity `v` is acted upon

1.	A proton (or charged particle) moving with velocity `v` is acted upon by electric field `E` and magnetic field `B`. The proton will move underflected ifA. E is perpenducular to BB. E is parallel to v and perpendicular to BC. E,B and v are mutually perpendicular and v=E/BD. E and B both are parallel to v
Answer» Correct Answer - C In this case `\|vecF_(e)\|=\|vecF_(m)\|` and both forces are opposite to each other.

Discussion

No Comment Found

Related InterviewSolutions

Two concentric coils of 10 turns each are placed in the same plane. Their radii are 20 cm and 40 cm and carry 0.2 A and 0.3 A current respectively in opposite directions. The magnetic induction (in tesla) at the centre isA. `3/4 mu_(0)`B. `5/4 mu_(0)`C. `7/4 mu_(0)`D. `9/4 mu_(0)`
Cyclotron is used to accelerateA. negative ionB. positive ionC. electronD. None of these
Assertion: Cyclotron is a device which is used to accelerate the position ions. Reason: Cyclotron frequency depends upon the velocity.A. If both the assertion and reason are true and reason is a true explantion of the assertion.B. If both the assertion and reason are true but the reason is not true the correct explantion of the assertion.C. If the assertion is true but reason falseD. If both the assertion and reason are false.
A wire is bent in the form of an equilateral triangle PQR of side 10 cm and carrise a current of 5.0 A. It is placed in a magnetic field B of magnitude 2.0 T directd perpendicularly to the plane of the loop. Find the forces on the three sides of the triangle.
An electron with kinetic energy 2.5 keV moving along the positive direction of an x axis enters a region in which a uniform electric field of magnitude 10 kV`//`m is in the negative direction of the y-axis. A uniform magnetic field `vecB` is to be set up to keep the electron moving along the x-axis , and the direction `vecB` of is to be chosen to minimize the required magnitude of `vecB`. In unit-vector notation, what `vecB` should be set up?
An electron and a proton are moving with the same kinetic energy along the same direction . When they pass through a uniform magnetic field perpendicular to the direction of their motion , they describe circular paths of the same radius.
A proton is moving along `Z`-axis in a magnetic field. The magnetic field is along `X`-axis. The proton will experience a force alongA. X-axisB. Y-axisC. Z-axisD. Negative Z-axis
A charged particle carrying charge `q=10 muC` moves with velocity `v_1=10^6 ,s^-1` at angle `45^@` with x-axis in the xy plane and experience a force `F_1=5sqrt2 mN` along the negative z-axis. When the same particle moves with velocity `v_2=10^6 ms^-1` along the z-axis, it experiences a force `F_2` in y-direction. Find the magnetic field `vecB`.A. `(10^-3T)(hati+hatj)`B. `(2xx10^-3T)hati`C. `(10^-3T)hati`D. `(2xx10^-3T)(hati+hatj)`
If a charged particle of charge `5 muC` and mass 5 g is moving with constant speed 5 m/s in a uniform magnetic field B on a curve `x^(2)+y^(2)=25`, where x and y are in meter. The value of magnetic field will beA. 1 teslaB. 1 kilo tesla along z-axisC. 5 kilo tesla along the x-axisD. 1 kilo tesla along any line in the x-y plane
In the figure shown there are two semicircles of radii `r_(1)` and `r_(2)` in which a current `i` is flowing. The magnetic induction at the centre `O` will be A. `(mu_(0) i)/(r) (r_(1) + r_(2))`B. `(mu_(0) i)/(4) (r_(1) -r_(2))`C. `(mu_(0) i)/(r) ((r_(1) + r_(2))/(r_(1) r_(2)))`D. `(mu_(0) i)/(r) ((r_(2) - r_(1))/(r_(1) r_(2)))`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment