1.

A quadrilateral ABCD is drawn to circumscribe a circle. Prove that `A B+C D=A D+B C`

Answer» Please refer to diagram in the video.
As we know, tangents drawn from a point to a circle are always equal.So,
`CR=CQ,PB=BQ,AP=AS and DR=DS`
So,`CR+PB+AP+DR = CQ+BQ+AS+DS`
`(CR+DR)+(PB+AP) = (CQ+BQ)+(AS+DS)`
As, `CS+DR = CD`
`PB+AP = AB`
`CQ+BQ=BC`
`AS+DS=AD`
So,`AB+CD = AD+BC`


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