A reaction rate contant doubles between 300 and 310 k. By which of the following factors does the rate constant increases between 400-410 K.

A reaction rate contant doubles between 300 and 310 k. By which of the

1.	A reaction rate contant doubles between 300 and 310 k. By which of the following factors does the rate constant increases between 400-410 K.
Answer» <html><body><p>3.39<br/>2<br/>1.48<br/>1.1</p>Solution :For any reaction , the value of <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> <a href="https://interviewquestions.tuteehub.com/tag/doubles-958969" style="font-weight:bold;" target="_blank" title="Click to know more about DOUBLES">DOUBLES</a> between 300 and 310 . For any other temp the rate constant decrease <br/> `"log"("log"(k_(2))/(k_(1)))/("log"(k_(2))/(k_(1)))=(10)/(400xx410)*(300xx310)/(10)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>'_(2)` and `k'_(1)` are rate constant at 410 and 400 K respectively. `k_(2)` and `k_(1)` are rate constant at 310 and 300 K respectively .Here `k_(2).k_(1)=2` <br/> `therefore "log"(k_(2)')/(k_(1)')=(3xx31)/(4xx41)xx"log"2` <br/> `=(3xx31xx0.3010)/(4xx41)=0.1707` <br/> `(k_(2))/(k_(1))`=antilog 0.1707 =1.48</body></html>