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A real-valued function f(x) satisfies the functional equation f(x−y)=f(x)f(y)−f(a−x)f(a+y) ∀ x,y ∈R, where a is a given constant and f(0)=1. Then, f(2a−x) is equal to |
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Answer» A real-valued function f(x) satisfies the functional equation f(x−y)=f(x)f(y)−f(a−x)f(a+y) ∀ x,y ∈R, where a is a given constant and f(0)=1. Then, f(2a−x) is equal to |
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