InterviewSolution
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InterviewSolution
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A resistor ` R_(1)` consumes electrical power `P_(1)` when connected to an `emf epsilon`. When resistor `R_(2)` is connected to the same `emf` , it consumes electrical power `P_(2)` . In terms of `P_(1) and P_(2)`, what is the total electrical power consumed when they are both connected to this emf source (a) in parallel (b) in series |
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Answer» Two resistance are `R_(1) a R_(2)`. Both consumed the Power `P_(1) and P_(2)` respectively. `P=(V^(2))/(R)therefore P_(1)=(V^(2))/(R_(1)) and P_(2)=(V^(2))/(R_(2))` `"(i) ""Power in series"=(1)/(P_(1))+(1)/(R_(2))=(R_(1))/(V^(2))+(R_(2))/(V^(2))=(R_(1)+R_(2))/(V^(2))` `"(ii) ""Power in parallel"=P_(1)+P_(2)` `" "=(V^(2))/(R_(1))+(V^(2))/(R_(2))=(V^(2)(R_(1)+R_(2)))/(R_(1)R_(2))` |
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