1.

A rhombus sheet, whose perimeter is 32 m and whose one diagonal is 10 m long, is painted on both sides at the rate of Rs. 5 per m2. Find the cost of painting.

Answer»

Since the sides of a rhombus are equal there fore each side = \(\frac{perimeter}4\) = \(\frac{22}4\) = 8 m

Let a, b and c are the sides of triangle and s is 

the semi-perimeter, then its area is given by:

A = \(\sqrt{s(s-a)(s-b)(s-c)}\)where s = \(\frac{a+b+c}2\)[Heron’s Formula]

s = \(\frac{a+b+c}2\) = \(\frac{8+8+10}2\) = 13

A = \(\sqrt{13(13-8)(13-8)(13-10)}\)

A = \(\sqrt{13\times5\times5\times3}\) = 31.22 cm2

Hence, area of rhombus ABCD = 2 ×31.22 m

= 62.44 m2

Total painting area of rhombus = 62.44 × 2 = 124.88 m

Cost of painting of rhombus on both sides = 124.88 × 5 = Rs 624.50



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