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A rigid and insulated tank of 3m^(3) volume is divided into two compartments. One second compartment of volume of 2m^(3) contains an ideal gas at 0.8314 Mpa and 400K and while the second compartment of volume 1m^(3) contains the same gas at 8.314 MPa and 500K. If the partition between the two compartments isruptured. the final temperature of the gas is:

Answer» <html><body><p>420K<br/>450K<br/>480K<br/>none of these</p>Solution :Number of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> in the first compartment = `(PV)/(RT) = (8.314 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(5) xx 2)/(8.314 xx 400) = 500`. Number of moles in the second compartment `=(8.314 xx 10^(6) xx 1)/(8.314 xx 500) = 2000` <br/> <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> lost by the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> in second compartment = Heat gained by the gas in first compartment <br/> So `2000 xx (500-T) xx <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> = 500 xx (T - 400)xx C` <br/> On solving, T= 480K</body></html>


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