A rigid and insulated tank of 3m^(3) volume is divided into two compartments. One second compartment of volume of 2m^(3) contains an ideal gas at 0.8314 Mpa and 400K and while the second compartment of volume 1m^(3) contains the same gas at 8.314 MPa and 500K. If the partition between the two compartments isruptured. the final temperature of the gas is:

A rigid and insulated tank of 3m^(3) volume is divided into two compar

1.	A rigid and insulated tank of 3m^(3) volume is divided into two compartments. One second compartment of volume of 2m^(3) contains an ideal gas at 0.8314 Mpa and 400K and while the second compartment of volume 1m^(3) contains the same gas at 8.314 MPa and 500K. If the partition between the two compartments isruptured. the final temperature of the gas is:
Answer» 420K 450K 480K none of these Solution :Number of MOLES in the first compartment = `(PV)/(RT) = (8.314 xx 10^(5) xx 2)/(8.314 xx 400) = 500`. Number of moles in the second compartment `=(8.314 xx 10^(6) xx 1)/(8.314 xx 500) = 2000` HEAT lost by the GAS in second compartment = Heat gained by the gas in first compartment So `2000 xx (500-T) xx C = 500 xx (T - 400)xx C` On solving, T= 480K