A rod of length 1 and radius .r. is joined to a rod of length 1/2 and radius r/2 material. The free end of small rod is fixed to a rigid base and the free and of larger rod is given a twist of theta. The twist angle at the joint will be

A rod of length 1 and radius .r. is joined to a rod of length 1/2 and

1.	A rod of length 1 and radius .r. is joined to a rod of length 1/2 and radius r/2 material. The free end of small rod is fixed to a rigid base and the free and of larger rod is given a twist of theta. The twist angle at the joint will be
Answer» <html><body><p></p>Solution :`theta_(1)+theta_(2)= theta to (1)` we know that `theta <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> (<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/(r^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))` <br/> `:.(theta_(1))/(theta_(2))=(l_(1))/(l_(2))xx(r_(2)^(4))/(r_(1^(4)))=(1//2)/(l)xx(r^(4))/((r//2)^(4))=<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>, (theta_(1))/(theta_(2))=8 to (2)` <br/> After solving equation (1) and (2), we get `theta_(1)=(8)/(9) theta`</body></html>