A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.5 M H_(2)SO_(4). The residual acid required 60 mL of 0.5 M solution of NaOH for neutralisation. What would be the percentage composition of nitrogen in the compound?

A sample of 0.50 g of an organic compound was treated according to Kje

1.	A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.5 M H_(2)SO_(4). The residual acid required 60 mL of 0.5 M solution of NaOH for neutralisation. What would be the percentage composition of nitrogen in the compound?
Answer» 50 60 56 44 Solution :Given: Mass of compound taken=0.50g VOL. of `H_(2)SO_(4)=50`mL Molarity of `H_(2)SO_(4)=0.5M` Vol. of NaOH required=60mL Molarity of NaOH requried=0.5M METHOD adopted Kjeldahl's method Formula used: % of N`=(1.4xxMxx2[V-(V_(1))/(2)])/(m)`. .(i) by substituting the vlaues in the formula, we GET `%` of `N=(1.4xx0.5xx2(50-60//2))/(0.5)=56` `therefore` % of N in the given compound=56%