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A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.5 M H_(2)SO_(4). The residual acid required 60 mL of 0.5 M solution of NaOH for neutralisation. What would be the percentage composition of nitrogen in the compound?

Answer» <html><body><p>50<br/>60<br/>56<br/>44</p>Solution :Given: <br/> Mass of compound taken=0.50g <br/> <a href="https://interviewquestions.tuteehub.com/tag/vol-723961" style="font-weight:bold;" target="_blank" title="Click to know more about VOL">VOL</a>. of `H_(2)SO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)=50`mL <br/> Molarity of `H_(2)SO_(4)=0.5M` <br/> Vol. of NaOH required=60mL <br/> Molarity of NaOH requried=0.5M <br/> <a href="https://interviewquestions.tuteehub.com/tag/method-559432" style="font-weight:bold;" target="_blank" title="Click to know more about METHOD">METHOD</a> adopted Kjeldahl's method <br/> Formula used: % of N`=(1.4xxMxx2[<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>-(V_(1))/(2)])/(m)`. .(i) <br/> by substituting the vlaues in the formula, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> <br/> `%` of `N=(1.4xx0.5xx2(50-60//2))/(0.5)=56` <br/> `therefore` % of N in the given compound=56%</body></html>


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