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A sample of a gas has a volume of 8.5dm^(3) at an unknown tempreture, When the sample is submerged in ice water at 0^(@)C, its volume gets reduce to 6.37dm^(3) .What is its intial tempreture? |
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Answer» Solution :`V_(1)=8.5dm^(3)``V_(2)=6.37dm^(3)` `T_(1)=?``T_(2)=0^(@)C=273K` `(V_(1))/(T_(1))=(V_(2))/(T_(2))` `V_(1)XX((T_(2))/(V_(2)))=T_(1)` `T_(1)=8.5cancel(dm^(3))xx(273 K)/(6.37cancel(dm^(3)))``T_(1)=364.28K` |
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