1.

A sample of a gas occupies 650.0 cm at 100^@C. At what temperature the gas will occupy a volume of 1050.0 cm^3if the pressure is kept constant ?

Answer»

Solution :In the present case,
`V_1 = 650.0 cm^3 "" V_2 = 1050.0 cm^3`
`T_1 = 100^@C = 100 + 273 = 373 K, "" T_2` = ?
The PRESSURE remains constant during expansion. Hence, ACCORDING to Charles. law
`V_1/T_1 = V_2/T_2`
or `T_2 = (V_2 T_1)/(V_1)=(1050.0 xx 373)/(650.0)= 602.5 K`
Hence, the required TEMPERATURE is `602.5 - 273 = 329.5^@C`.


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