InterviewSolution
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InterviewSolution
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A sample of air consisting of `N_(2) and O_(2)` was heated to 2500 K until the equilibrium `N_(2) (g) + O_(2) (g) hArr 2 NO (g)` was established the intial composition of air in mole fraction of `N_(2) and O_(2).` |
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Answer» `{:(,N_(2)(g),+,O_(2),hArr,2NO,),("Intial ",a,,b,,0,),(,,,,,,a+b = 100" " ...(ii)),("At eqm",a-x,,b-x,,2x,):}` ` K_(c) = (2x)^(2) /((a-x)(b-x)) = (4x^(2))/((a-x)(b-x))` In the question , we are given `2x = 1*8 ("because total moles " =100)` or ` x= 0*9 and K_(c) = 2*1 xx 10^(-3) ` ` :. 2*1 xx 10^(-3) = (1*8)^(2)/((a-0*9 )(b-0*9)) ` ` ab - 0*9 a- 0*9 b + 0*81 = 1620` ` ab - 0*9 (a+b) + 0*81 = 1620 ` ` ab- 0*9 xx 100 + 0*81 = 1620 ` ` or ab = 1909 * 19 = 1709` ` Now (a-b)^(2) = (a+b)^(2) - 4 ab = (100)^(2) - 4 xx 709 = 3164 ` or ` a-b = sqrt (3164)= 56*2 " " `...(ii) Solving (i) and (ii), `a= 78*1 "moles"` Moles fraction of ` N_(2) = (78*1 )/100 = 0* 781 ` Mole fraction of ` O_(2) = 1 - 0* 781 = 0* 219 ` |
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