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A sample of gas occupies 12 L at 227^@C and at 1 atm pressure. The gas is cooled to - 73^@C at the same pressure. What would be the volume of the gas?

Answer» <html><body><p></p>Solution :Given that, <br/> `V_1 = 12 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>, "" V_2` =? <br/>`T_1 = 227 + <a href="https://interviewquestions.tuteehub.com/tag/273-1832932" style="font-weight:bold;" target="_blank" title="Click to know more about 273">273</a> = 500 K, " " T_2= -73 + 273 = 200 K` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> remains constant during cooling। Hence, <a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to Charles. law, we have <br/> `V_1/T_1 = V_2/T_2`<br/>or `V_2 = (V_1 T_2)/(T_1) =(12xx 200)/(500) = 4.8 L`<br/>Hence, on cooling the volume of the given <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> reduces to 4.8 L.</body></html>


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