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A sample of gas occupies 12 L at 227^@C and at 1 atm pressure. The gas is cooled to - 73^@C at the same pressure. What would be the volume of the gas? |
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Answer» Solution :Given that, `V_1 = 12 L, "" V_2` =? `T_1 = 227 + 273 = 500 K, " " T_2= -73 + 273 = 200 K` The PRESSURE remains constant during cooling। Hence, ACCORDING to Charles. law, we have `V_1/T_1 = V_2/T_2` or `V_2 = (V_1 T_2)/(T_1) =(12xx 200)/(500) = 4.8 L` Hence, on cooling the volume of the given GAS reduces to 4.8 L. |
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