A sample of H_(2)O_(2) is x % by mass. If x ml of KMnO_(4) are required to oxidize 1 gm of this H_(2)O_(2) sample, calculate the normality of KMnO_(4) solution.

A sample of H_(2)O_(2) is x % by mass. If x ml of KMnO_(4) are require

1.	A sample of H_(2)O_(2) is x % by mass. If x ml of KMnO_(4) are required to oxidize 1 gm of this H_(2)O_(2) sample, calculate the normality of KMnO_(4) solution.
Answer» `0.46N` `0.5N` `0.6N` `0.65N` Solution :Let mass of `H_(2)O_(2)` solution = 100 gm mass of `H_(2)O_(2)` present is = XGM GIVEN that mass of `H_(2)O_(2)` solution taken = 1 gm, So, mass of `H_(2)O_(2)` present in 1 gm solution `=(x)/(100)` Eq. of `H_(2)O_(2)=(x)/(100xx(34//2))` Eq. of `KMnO_(4)=NxxV(C)=Nxx x xx10^(-3)` Now `(x)/(100xx17)=Nxx x xx10^(-3)impliesN=0.59N`