A sample of HI(g) is placed in a flask a pressure of 0.2 atm. At equilibrium partial pressure of HI(g) is 0.04atm. What is K_p for the given equilibrium ? 2HI(g) hArr H_(2)(g) + I_(2)(g)

A sample of HI(g) is placed in a flask a pressure of 0.2 atm. At equil

1.	A sample of HI(g) is placed in a flask a pressure of 0.2 atm. At equilibrium partial pressure of HI(g) is 0.04atm. What is K_p for the given equilibrium ? 2HI(g) hArr H_(2)(g) + I_(2)(g)
Answer» Solution :`PHI =0.04` ATM `pH_2 = 0.08` atm `Pl_(2)` =0.08 atm `K_(p) = (PH_2 xxpl_2)/(P_(HI)^2) = ((0.08 atm )xx(0.08))/((0.04 atm ) xx (0.04 atm))=4.0`