A sample of HI(g) is placed in a flask a pressure of 0.2 atm. At equilibrium partial pressure of HI(g) is 0.04atm. What is K_p for the given equilibrium ? 2HI(g) hArr H_(2)(g) + I_(2)(g)

A sample of HI(g) is placed in a flask a pressure of 0.2 atm. At equil

1.	A sample of HI(g) is placed in a flask a pressure of 0.2 atm. At equilibrium partial pressure of HI(g) is 0.04atm. What is K_p for the given equilibrium ? 2HI(g) hArr H_(2)(g) + I_(2)(g)
Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/phi-599602" style="font-weight:bold;" target="_blank" title="Click to know more about PHI">PHI</a> =0.04` <a href="https://interviewquestions.tuteehub.com/tag/atm-364409" style="font-weight:bold;" target="_blank" title="Click to know more about ATM">ATM</a> `pH_2 = 0.08` atm `Pl_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` =0.08 atm <br/> `K_(p) = (PH_2 xxpl_2)/(P_(HI)^2) = ((0.08 atm )xx(0.08))/((0.04 atm ) xx (0.04 atm))=4.0`</body></html>