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A sample of HI (g) is placed in a flask at a pressure of 0*2 atm. At equilibrium , the partial pressure of HI (g) is 0*04 atm . What is K_(p) for the given equilibrium ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :` {:(,2 <a href="https://interviewquestions.tuteehub.com/tag/hi-479908" style="font-weight:bold;" target="_blank" title="Click to know more about HI">HI</a>(g),hArr,H_(2)(g),+,I_(2)), (" Intial pressure",0*2"atm",,0,,0), ("At <a href="https://interviewquestions.tuteehub.com/tag/eqm-446398" style="font-weight:bold;" target="_blank" title="Click to know more about EQM">EQM</a>",0*04,,(0*16)/2,,(0*16)/2),(,,,=0*8"atm",,=0*8 "atm"),(,,,,,("Decease in the pressure <a href="https://interviewquestions.tuteehub.com/tag/pf-1152667" style="font-weight:bold;" target="_blank" title="Click to know more about PF">PF</a> Hi" = 0*2 - 0*04 = 0*16 "atm")):}`<br/> ` :. K_(p) = ( pH_(2) xx pI_(2))/(p_(HI_(2))) = ( 0*8 "atm " xx 0*08 "atm")/(0*04 "atm")^(2)= 4*0 . `</body></html>


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