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A sample of hydrochloric acid contains 20 % hydrochloric acid by weight. How much of this acid is required for the complete reduction of 50 g of calcium carbonate ?

Answer» <html><body><p><br/></p>Solution :Chemical equation for the reaciton is : <br/> `underset(underset(=100g)(40+12+48))(CaCO_(3))+underset(underset(=73g)(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(1+35.5)))(2HCl)rarrCaCl_(2)+H_(2)O+CO_(2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> g of calcium carbonate require acid = <a href="https://interviewquestions.tuteehub.com/tag/73-334616" style="font-weight:bold;" target="_blank" title="Click to know more about 73">73</a> g <br/> 50 g of calcium carbonate require acid `= (73)/(100) xx 50 = 36.5 g` <br/> Mass of the <a href="https://interviewquestions.tuteehub.com/tag/sample-1194587" style="font-weight:bold;" target="_blank" title="Click to know more about SAMPLE">SAMPLE</a> of hydrochloric `= 36.5 xx (100)/(20) = 182.5 g`.</body></html>


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