A sample of N_(2)O_(4(g)) with a pressure of I atm is placed in a flask. When equilibrium is reached, 20% N_(2)O_(4(g)) has been converted to NO_(2(g)) .N_(2)O_(4(g)) hArr 2NO_(2(g)), If the orginal pressure is made 10% of the earlier, then percent dissociation will be

A sample of N_(2)O_(4(g)) with a pressure of I atm is placed in a flas

1.	A sample of N_(2)O_(4(g)) with a pressure of I atm is placed in a flask. When equilibrium is reached, 20% N_(2)O_(4(g)) has been converted to NO_(2(g)) .N_(2)O_(4(g)) hArr 2NO_(2(g)), If the orginal pressure is made 10% of the earlier, then percent dissociation will be
Answer» 0.2 0.42 0.54 0.62 Solution : Parpal pressure `((1-x)/(1+x))P, ((2x)/(1+x))P` `K_(P)=(4x^(2)P)/(1-x^(2))` In case-I: P=1 atm and x = 0.20 In case II : P=0.1 atm 10% of the EARLIER pressure and x=? `(4(0.2)^(2) XX 1)/([1-(0.2)^(2)])=(4x^(2)(0.1))/(1-x^(2))` `(0.04)/(1-0.04)=(x^(2)(0.1))/((1-x^(2)))(x^(2))/(1-x^(2))=0.4167` `x^(2)=0.2941, x=0.2941 IMPLIES` THUS 54.23%