1.

A sample of nitric acid is 55 per cent by mass. Calculate the mass of nitric acid present in 100 cm of the sample if its density is 1.36 g cm^(-3).

Answer» <html><body><p></p>Solution :Since, the given sample is 55% by mass, 100 g of the sample would <a href="https://interviewquestions.tuteehub.com/tag/contain-409810" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAIN">CONTAIN</a> 55 g of `HNO_3`. <br/> Since, <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> `=("mass")/("volume")` <br/> Therefore, the volume of 100 g of the sample `=("mass")/("density") = 100/(1.36) = 73.5 cm^(3)` <br/> Thus,73.5 cm of the given sample contains 55 g of `HNO_3`. <br/> Hence, the mass of `HNO_3` present in 100 cm of the sample <br/> `=55/(73.5) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 100 = 74.8 g`</body></html>


Discussion

No Comment Found