1.

A sample of nitric acid is 55 per cent by mass. Calculate the mass of nitric acid present in 100 cm of the sample if its density is 1.36 g cm^(-3).

Answer»

Solution :Since, the given sample is 55% by mass, 100 g of the sample would CONTAIN 55 g of `HNO_3`.
Since, DENSITY `=("mass")/("volume")`
Therefore, the volume of 100 g of the sample `=("mass")/("density") = 100/(1.36) = 73.5 cm^(3)`
Thus,73.5 cm of the given sample contains 55 g of `HNO_3`.
Hence, the mass of `HNO_3` present in 100 cm of the sample
`=55/(73.5) XX 100 = 74.8 g`


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