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A sample of nitrogen gas occupies a volume of 1 L at a pressure of 0.5 bar at 40^@C. Calculate the pressure if the gas is compressed to 0.225 cm^3"at" -6^@C |
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Answer» Solution :In the present case, `P_1 = 0.500` atm, `V_1 = 1.000 L`, `T_1 = 273 + 40 = 313 K " and " P_2` =?, `V_2 = 0.225 cm^3 =(0.225)/(1000)L`, `T_2 = -6+ 273 = 267 K` ( `:.10^3 cm^3 = 1 L)` According to the gas EQUATION, `(P_1 V_1)/T_1 = (P_2 V_2)/T_2` On substituting the values, we have `(0.500 xx 1.000)/313 = (p_2 xx (0.225)/1000)/267` `:. "" P_2 = 1.89xx10^3` atm Therefore, the GIVEN gas should be compressed to a pressure of `1.89 xx 10^3` atm. |
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