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A sample of nitrogen gas occupies a volume of 1 L at a pressure of 0.5 bar at 40^@C. Calculate the pressure if the gas is compressed to 0.225 cm^3"at" -6^@C

Answer» <html><body><p></p>Solution :In the present case, <br/> `P_1 = 0.500` atm, <br/> `V_1 = 1.000 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>`, <br/> `T_1 = 273 + <a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a> = 313 K " and " P_2` =?, <br/> `V_2 = 0.225 cm^3 =(0.225)/(<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a>)L`, <br/>`T_2 = -6+ 273 = 267 K` <br/> ( `:.10^3 cm^3 = 1 L)` <br/>According to the gas <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a>, `(P_1 V_1)/T_1 = (P_2 V_2)/T_2`<br/> On substituting the values, we have <br/> `(0.500 xx 1.000)/313 = (p_2 xx (0.225)/1000)/267` <br/> `:. "" P_2 = 1.89xx10^3` atm <br/> Therefore, the <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> gas should be compressed to a pressure of `1.89 xx 10^3` atm.</body></html>


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