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A sample of nitrogen gas occupies a volume of 320cm^(3) at STP. Calculate its volume at 66^(@)C and 0*825 bar presssure. |
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Answer» Solution :Here , `P_(1)1*00 "BAR", P_(2) 0*825`bar `V_(1)=320 cm^(3) "" V_(2)=?` `T_(1)=273*15K "" T_(2)66^(@)C=339*15 K` According to the GAS equation, `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))=(1xx320xx339)/(273xx0*825)=481*6 cm^(3)` `v_(2)=481*6 cm^(3)` |
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