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A sample of pure PCl_(5) was introduced into an evacuted vessel at 473 K. After equilibrium ws attained , concentration of Pcl_(5) was found to be 0*5 xx 10^(-1)"mol" L^(-1). If value of K_(c)" is "8*3 xx 10^(-3), what are the concentrations of PCl_(3) and Cl_(2) at equilibrium ? |
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Answer» Solution :` {:(,PCl_(5)(g),HARR,PCl_(3)(g),+,Cl_(2)(g),), ("At eqm.", 0*5 xx 10^(-1)"mol"L^(-1),,x"mol"L^(-1),,x"mol"L^(-1),("suppose")):}` ` :. K_(c) (x^(2))/(0*5 xx 10^(-1)) = 8*3 xx10^(-3) ("Given")` or `x^(2) = (8*3 xx 10^(-3))(0*5 xx 10^(-1)) = 4* 15 xx 10^(-4)` or ` x = sqrt(4*15 xx 10^(-4))= 2*04 xx 10^(-2)"M" = 0 *02 "M"` Hence, `[PCl_(3)]_(eq) = [Cl_(2)]_(eq) = 0*02 " M"` |
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