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A sample of pure PCl_(5) was introduced into an evacuted vessel at 473 K. After equilibrium ws attained , concentration of Pcl_(5) was found to be 0*5 xx 10^(-1)"mol" L^(-1). If value of K_(c)" is "8*3 xx 10^(-3), what are the concentrations of PCl_(3) and Cl_(2) at equilibrium ?

Answer» <html><body><p></p>Solution :` {:(,PCl_(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)(g),<a href="https://interviewquestions.tuteehub.com/tag/harr-2692945" style="font-weight:bold;" target="_blank" title="Click to know more about HARR">HARR</a>,PCl_(3)(g),+,Cl_(2)(g),), ("At eqm.", <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>*5 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)"mol"L^(-1),,x"mol"L^(-1),,x"mol"L^(-1),("suppose")):}` <br/> ` :. K_(c) (x^(2))/(0*5 xx 10^(-1)) = 8*3 xx10^(-3) ("Given")` <br/> or `x^(2) = (8*3 xx 10^(-3))(0*5 xx 10^(-1)) = 4* <a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> xx 10^(-4)`<br/>or ` x = sqrt(4*15 xx 10^(-4))= 2*04 xx 10^(-2)"M" = 0 *02 "M"`<br/> Hence, `[PCl_(3)]_(eq) = [Cl_(2)]_(eq) = 0*02 " M"`</body></html>


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