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A sample of sucrose is found to contain 72.28 xx 10^21 atoms of carbon. Find the mass of the sample in grams.

Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> formula of sucrose is `C_12H_22O_11`. From this formula, it is evident that one mole of sucrose <a href="https://interviewquestions.tuteehub.com/tag/contains-11473" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINS">CONTAINS</a> 12 gram atoms of carbon. The molecular mass of sucrose is`(12 xx 12.01) + (22 xx 1.008) + (11 xx 16.0) = 342.296` amu. <br/> Since, 1 gram atom of carbon contains `6.022 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>)`atoms, the number of gram atoms <a href="https://interviewquestions.tuteehub.com/tag/corresponding-935567" style="font-weight:bold;" target="_blank" title="Click to know more about CORRESPONDING">CORRESPONDING</a> to <br/> `72.28 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/21-293276" style="font-weight:bold;" target="_blank" title="Click to know more about 21">21</a>)` atoms `=(72.28 xx 10^(21))/(6.022 xx 10^(23)) = 0.1200` <br/> `therefore` The gram moles of sucrose which contain 0.12 gram atoms of carbon `=1/12 xx 0.1200 = 0.0100` <br/> `therefore` The mass of 0.0100 moles of sucrose `=0.0100 xx 342.296 = 3.423 g`</body></html>


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