1.

A sampleof air consisting of N_(2) and O_(2) was heated to 2500 K until the equilibrium N_(2) (g) + O_(2) (g) hArr 2 NO (g) was established the intial composition of air in mole fraction of N_(2) and O_(2).

Answer» <html><body><p></p>Solution :`{:(,N_(2)(g),+,O_(2),hArr,2NO,),("Intial ",a,,b,,0,),(,,,,,,a+b = <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>"" ...(ii)),("At eqm",a-x,,b-x,,2x,):}` <br/> ` K_(c)= (2x)^(2) /((a-x)(b-x)) = (4x^(2))/((a-x)(b-x))` <br/> In the question , we are given `2x = 1*8 ("because total moles " =100)`<br/> or ` x= 0*9 and K_(c) = 2*1 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) ` <br/>` :. 2*1 xx 10^(-3) = (1*8)^(2)/((a-0*9 )(b-0*9)) ` <br/> ` ab - 0*9 a- 0*9 b + 0*81 = <a href="https://interviewquestions.tuteehub.com/tag/1620-1794901" style="font-weight:bold;" target="_blank" title="Click to know more about 1620">1620</a>`<br/> ` ab - 0*9 (a+b) + 0*81 = 1620 ` <br/> ` ab- 0*9 xx 100 + 0*81 = 1620 `<br/> ` or ab = 1909 * 19 = 1709` <br/> ` Now(a-b)^(2) = (a+b)^(2) - 4 ab = (100)^(2)- 4 xx 709 = 3164 ` <br/> or ` a-b = sqrt (3164)= 56*2 "" `...(ii) <br/> Solving (i) and (ii), `a= 78*1 "moles"` <br/> Moles fraction of` N_(2) = (78*1 )/100 = 0* 781 `<br/> Mole fraction of ` O_(2) = 1 - 0* 781 = 0* 219 `</body></html>


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