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A saturated solution of o- nitrophenol has a pH equal to 4.53 then its solubility in water is (pK_a=7.23) |
Answer» <html><body><p>` 2.085 g//"lit"` <br/>` 20. 85 g //"lit"` <br/>` 10. 425g//"lit"` <br/>` 1.0425 g//"lit"` </p>Solution :` O- " nitrophenol" _(s) hArr O- " nitro <a href="https://interviewquestions.tuteehub.com/tag/phenol-1152951" style="font-weight:bold;" target="_blank" title="Click to know more about PHENOL">PHENOL</a> "_((aq) ) ` <br/> ` O- "nitrophenol"_((aq)) hArr O- " nitro phenol " + H^(+) ` <br/> ` S(1-<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> )"" S alpha "" S alpha ` <br/> ` [H^(+) ]=S alpha =sqrt( SKa) ` <br/> ` -log [H^(+) ] =(-log S -log Ka)/( 2) ` <br/> ` <a href="https://interviewquestions.tuteehub.com/tag/ph-1145128" style="font-weight:bold;" target="_blank" title="Click to know more about PH">PH</a> =(-log S - log Ka )/( 2) ` <br/> ` pH =(- log S +<a href="https://interviewquestions.tuteehub.com/tag/pka-1145194" style="font-weight:bold;" target="_blank" title="Click to know more about PKA">PKA</a>)/( 2) `<br/> ` - log S = 2xx 4.53 -7.23 =1.83` <br/> ` rArr S = 1 .48 xx 10 ^(-2)"mol" //"lit" ` <br/> ` M. wt = 139 rArr S =2.06 g//lit `</body></html> | |