A sea diver at depth of 45m exhales a bubble of air that is 1.0 cm in radius. Assuming the ideal behaviour, find out radius of this bubble as it breaks at the surface of water?

A sea diver at depth of 45m exhales a bubble of air that is 1.0 cm in

1.	A sea diver at depth of 45m exhales a bubble of air that is 1.0 cm in radius. Assuming the ideal behaviour, find out radius of this bubble as it breaks at the surface of water?
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.75 cm <br/>1.50 cm <br/>1.25 cm <br/>0.75 cm </p>Solution :Pressure of <a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a> m <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> in terms of mercury level : <br/> `h_1d_1 = h_2d_2` <br/>`45 xx 1 = h_2 xx 13.6 = <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> = 3.3 m`. <br/> `:.` Pressure at 45 m depth = `(0.76 + 3.3) = 4.06 m.` <br/> `P_1V_1 = P_2V_2` <br/> `4.06 xx 4/3 pi (1)^3 = 0.76 xx 4/3 pi (r_(cm))^(3)` <br/> `implies r_(cm) root(3)((4.06)/(0.76)) , r_(cm) = 1.75 cm`</body></html>