A set of n identical cubical blocks lies at rest parallel to each other along a line on a smooth horizontal surface. The separation between the near surfaces of any two adjacent blocks is L . The block at one end is given a speed v towards the next one at time 0 t . All collisions are completely inelastic, thenA. The last block starts moving at `t = n (n - 1) (L)/(2v)`B. The last block starts moving `t = (n - 1) (L)/(v)`C. The centre of mass of the system will have a final speed `(v)/(n)`D. The centre of mass of the system will have a final speed `v`.

A set of n identical cubical blocks lies at rest parallel to each othe

1.	A set of n identical cubical blocks lies at rest parallel to each other along a line on a smooth horizontal surface. The separation between the near surfaces of any two adjacent blocks is L . The block at one end is given a speed v towards the next one at time 0 t . All collisions are completely inelastic, thenA. The last block starts moving at `t = n (n - 1) (L)/(2v)`B. The last block starts moving `t = (n - 1) (L)/(v)`C. The centre of mass of the system will have a final speed `(v)/(n)`D. The centre of mass of the system will have a final speed `v`.
Answer» Correct Answer - A::C `t_(1) = (L)/(v)` (time for `1st` collision) `t_(2) = (2L)/(v)` (time for IInd collision ) `t_(3) = (3L)/(v)` (time for 3rd collision) `t_(n - 1) = (L)/(v) (n - 1)` (time for `(n^(th))` collision) `underset(1 - 1)overset(h)sum t_(1) = (n(n - 1))/(2) (L)/(v)`

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