A signal which can be green or red with probability `4/5 and 1/5` respectively, is received by station A and then and 3 transmitted to station B. The probability of each station receiving the signal correctly is `3/4` If the signal received at station B is green, then the probability that the original signal was green is (a) `3/5` (b) `6/7` (d) `20/23` (d) `9/20`

A signal which can be green or red with probability `4/5 and 1/5` resp

1.	A signal which can be green or red with probability `4/5 and 1/5` respectively, is received by station A and then and 3 transmitted to station B. The probability of each station receiving the signal correctly is `3/4` If the signal received at station B is green, then the probability that the original signal was green is (a) `3/5` (b) `6/7` (d) `20/23` (d) `9/20`
Answer» acc to the question `P = (4/53/43/4 + 4/51/41/4) + (1/53/41/4 + 1/51/43/4)` `P = 46/80 = 23/40` `P [or G] = 40/80 = 20/40` `P= (20/40)/(23/40)= 20/23`

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