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A simple pendulum, suspended from the coiling of a lift, has a period of oscillation T, when the lift is at rest. If the lift starts moving upwards with an acceleration a =3g, then the new period will beA. T/2B. 2TC. T/3D. 3T |
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Answer» Correct Answer - A The period of pendulum when lift is stationary `T=2pisqrt((L)/(g))` When the lift is moving upwards, the acceleration of the lift increases. `therefore T_(1)=2pisqrt((L)/(g+a))=2pisqrt((L)/(g+3g))=2pisqrt((L)/(4g))` `(T_(1))/(T)=sqrt((g)/(4g))=(1)/(2) therefore T_(1)=(T)/(2)` |
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