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A siren placed at a railway platform is emitting sound of frequency `5 kHz`. A passenger sitting in a moving train `A` records a frequency of `5.5kHz` while the train approaches the siren. During his return journey in a different train `B` he records a frequency of `6.0 kHz` while approaching the same siren. the ratio the velocity of train `B` to that of train `A` isA. `(242)/(252)`B. 2C. `(5)/(6)`D. `(11)/(6)` |
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Answer» Correct Answer - D `f_(approach)_(A)=5.5kHz=((v+v_A)/(v))5` ..(i) `f_(approach)_(B)=6kHz=((v+v_B)/(v))5` ..(ii) Where `v` is the velocity of sound. Now, `5.5=(1+(v_A)/(v))5` `implies(v_A)/(v)=0.1` .(iii) similarly, `6=(1+(v_B)/(v))5` `implies(v_B)/(v)=0.2` .(iv) `implies(v_B)/(v_A)=2` |
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