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A small ball travels with a speed vo over a fixed wedge as shown in the figure. The minimum value of so that the particle doesn't hit the inclined plane, will beO tan/29HCOSVo√29H)O tan-1 IgH​

Answer» <html><body><p>tion:Method 1 : Analysis of forces on m relative to groundIF the <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> of m is analyzed from ground, its acceleration is A and the forces acting on it are its weight <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> and normal reaction N. Asm is at rest, moving with same acceleration as wedge in horizontal direction but in vertical direction, the block is at rest. ∑ F y =0⇒Ncosθ=mg........(i) ∑ F <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> =∑m i a i ⇒Nsinθ=mA.........(ii)On solving (i) and (ii), we get A=gtanθ and N= cosθmg Method <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> : Analysis of forces on m relative to the inclined planeIf the motion of m is analyzed from the view point of an observer <a href="https://interviewquestions.tuteehub.com/tag/standing-651653" style="font-weight:bold;" target="_blank" title="Click to know more about STANDING">STANDING</a> on the inclined plane (i.e., relative to the plane), its acceleration is 0 and the forces acting on it are : its weight. the normal reaction and a pseudo force of magnitude mA towards left. mAsinθ=mAcosθ⇒ A=gtanθAlso: N=mgcosθ+mAsinθ mgcosθ+mgtanθsinθ= cosθmg solution</p></body></html>


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