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A small source of sound vibrating at frequency 500 Hz is rotated in a circle of radius 100/2pi cm at a constant angular speed of 5-0 revolutions per second. A listener situates himself in the plane of the circle. Find the minimum and the maximum frequency of the sound observed. Speed of sound in air = 332 m s^-1. |
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Answer» `Radius of the circle `=100/picm` `=100/pixx10^-2m` `=(1/pi)METRES` `omega=5rev/sec` So the linear speed `v=omegar=5/pi=(1.59)` so, velocity of the SOURCE `V_s=1.59m/s` so the at the position A the observer will listen maximum and at the position B it will listen MINIMUM frequency. So apparent frequency at A `=(332/(332+159))xx500~~515Hz` So apparent frequency at B `=(332/((332+159))xx500~~485GHz` |
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