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A small source of sound vibrating at frequency 500 Hz is rotated in a circle of radius 100/2pi cm at a constant angular speed of 5-0 revolutions per second. A listener situates himself in the plane of the circle. Find the minimum and the maximum frequency of the sound observed. Speed of sound in air = 332 m s^-1.

Answer» <html><body><p><br/></p>Solution :Acording to given data <br/> `Radius of the circle `=100/picm` <br/> `=100/pixx10^-2m` <br/> `=(1/pi)<a href="https://interviewquestions.tuteehub.com/tag/metres-1095332" style="font-weight:bold;" target="_blank" title="Click to know more about METRES">METRES</a>` <br/> `omega=5rev/sec` <br/> So the linear speed <br/> `v=omegar=5/pi=(1.59)` <br/> so, velocity of the <a href="https://interviewquestions.tuteehub.com/tag/source-1219297" style="font-weight:bold;" target="_blank" title="Click to know more about SOURCE">SOURCE</a> <br/> `V_s=1.59m/s` <br/> so the at the position A the observer will listen maximum and at the position <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> it will listen <a href="https://interviewquestions.tuteehub.com/tag/minimum-561095" style="font-weight:bold;" target="_blank" title="Click to know more about MINIMUM">MINIMUM</a> frequency. <br/> So apparent frequency at A <br/> `=(<a href="https://interviewquestions.tuteehub.com/tag/332-1856202" style="font-weight:bold;" target="_blank" title="Click to know more about 332">332</a>/(332+159))xx500~~515Hz` <br/> So apparent frequency at B <br/> `=(332/((332+159))xx500~~485GHz`</body></html>


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