1.

A solid A^(+)B^(-) has NaCl close packed structure. The radius of thecation when the radius of the anion is 250 pm is

Answer»

103.5 pm
207 pm
69 pm
276 pm

Solution :Since the solid `A^(+) B^(-)`has NaCl type close packed structure, it belongs to a system with coordination number 6. In thesecases the ratio of the cation to the anion radii is GIVEN by
`R^(+)/r^(-)ge0.414`
`"Now" r^(-)=250"pm"`
`thereforer^(+)=250times0.414=103.5"pm"`


Discussion

No Comment Found