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A solid A^(+)B^(-) has NaCl close packed structure. The radius of thecation when the radius of the anion is 250 pm is |
Answer» <html><body><p>103.5 pm<br/>207 pm<br/>69 pm <br/>276 pm</p>Solution :Since the solid `A^(+) <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>^(-)`has NaCl type close packed structure, it belongs to a system with coordination number <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>. In thesecases the ratio of the cation to the anion radii is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by<br/> `<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(+)/r^(-)ge0.414`<br/> `"Now" r^(-)=<a href="https://interviewquestions.tuteehub.com/tag/250-297421" style="font-weight:bold;" target="_blank" title="Click to know more about 250">250</a>"pm"` <br/> `thereforer^(+)=250times0.414=103.5"pm"`</body></html> | |