A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion (Y^-) will be

A solid compound XY has NaCl structure. If the radius of the cation is

1.	A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion (Y^-) will be
Answer» <html><body><p>275.1<br/>322.5 <a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a><br/>241.5 pm<br/>165.7 pm</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/nacl-572483" style="font-weight:bold;" target="_blank" title="Click to know more about NACL">NACL</a> has face-centred cubic arrangement of `Cl^-` <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> and `<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a>^+` ions are present in the octahedral voids. Hence, for such a <a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a> radius of cation =0.414 xradius of the anion ( or `r_+/r_(-)`=0.414) <br/> i.e., `r_+= 0.414xxr_(-)` <br/> or `r_(-)=r_+/0.414=100/0.414`=241.5 pm</body></html>