1.

A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion (Y^-) will be

Answer»

275.1
322.5 PM
241.5 pm
165.7 pm

Solution :NACL has face-centred cubic arrangement of `Cl^-` IONS and `NA^+` ions are present in the octahedral voids. Hence, for such a SOLID radius of cation =0.414 xradius of the anion ( or `r_+/r_(-)`=0.414)
i.e., `r_+= 0.414xxr_(-)`
or `r_(-)=r_+/0.414=100/0.414`=241.5 pm


Discussion

No Comment Found