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A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion `(Y^-)` will beA. 275.1B. 322.5 pmC. 241.5 pmD. 165.7 pm |
Answer» Correct Answer - C NaCl has face-centred cubic arrangement of `Cl^-` ions and `Na^+` ions are present in the octahedral voids. Hence, for such a solid radius of cation =0.414 x radius of the anion ( or `r_+/r_(-)`=0.414) i.e., `r_+= 0.414xxr_(-)` or `r_(-)=r_+/0.414=100/0.414`=241.5 pm |
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