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InterviewSolution
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A solid consisting of a right circular cone of height 120 cm and radius 60 cm standing ona hemisphere of radius 60 cm is placed upright in a right circular cylinder full of watersuch that it touches the bottom. Find the volume of water left in the cylinder, f the radiunof the cylinder is 60 cm and its height is 180 cm.. |
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Answer» We have,Radius of cylinder = Radius of cone = Radius of hemisphere = 60 cmHeight of cone = 120 cmHeight of cylindrical vessel = 120 + 60 = 180 cm Volume of cylinder =πr^2h =22/7 x(60)^2x180 Now, volume of the solid= Volume of cone + Volume of hemisphere =1/3*22/7*(60)^2*120+2/3*22/7*(60)^3 Volume of water left in the cylinder= Volume of the cylinder – Volume of the solid=22/7*(60)^2*180-1/3*22/7*(60)^2=22/7*3600*(180-40-40)=792/700m^3=1.131m^3 |
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