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A solid whose volume does not change with temperature floats in a liquid. For two different temperatures `t_1` and `t_2` of the liqiud, fraction `f_1` and `f_2` of the volume of the solid remain submerged in the liquid. The coefficient of volume expansion of the liquid is equal toA. `(f_(1)-f_(2))/(f_(2)t_(1)-f_(2)t_(1))`B. `(f_(1)-f_(2))/(f_(2)t_(1)-f_(2)t_(1))`C. `(f_(1)+f_(2))/(f_(2)t_(1)+f_(2)t_(1))`D. `(f_(1)+f_(2))/(f_(2)t_(1)+f_(2)t_(1))` |
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Answer» Correct Answer - A `W+p_(t_1)f_(1)Vg=rho_(t_(2))f_(2)vg` `rho_(t_(1))f_(1)=rho_(t_(2))f_(2)` `(rho_(0)/(1+gammat_(2)))f_(1) =(rho_(0)/(1+gammat_(0)))f_(2)` `(1+gammat_(2))f_(1)=(1+gammat_(1))f_(2)` `f_(1)-f_(2)=(f_(2)t_(1)-f_(1)t_(2))` `gamma=(f_(1)-f_(2))/(f_(2)t_(1)-f_(1)t_(2))` |
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