A solution consists of 0.2 MNH_4 OH and 0.2 MNH_4Cl .If K_b of NH_4 OH is 1. 8 xx 10 ^(-5), the [OH^(-) ] of the resulting solution is

A solution consists of 0.2 MNH_4 OH and 0.2 MNH_4Cl .If K_b of NH_4 OH

1.	A solution consists of 0.2 MNH_4 OH and 0.2 MNH_4Cl .If K_b of NH_4 OH is 1. 8 xx 10 ^(-5), the [OH^(-) ] of the resulting solution is
Answer» <html><body><p>`0.9 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10 ^(-5) M` <br/>` 1.8 xx 10 ^(-5) ` <br/>` 3.2 xx 10 ^(-5) M` <br/>` 3. <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> xx 10 ^(-5) ` M </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/poh-1145204" style="font-weight:bold;" target="_blank" title="Click to know more about POH">POH</a> =P^(K_b)+ log ""( [S])/([<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>]) ` <br/>If ` [S] =[B] rArr pOH = P^(K_b) rArr [OH^(-) ] =K_b`</body></html>