1.

A solution consists of 0.2 MNH_4 OH and 0.2 MNH_4Cl .If K_b of NH_4 OH is 1. 8 xx 10 ^(-5), the [OH^(-) ] of the resulting solution is

Answer»

`0.9 XX 10 ^(-5) M`
` 1.8 xx 10 ^(-5) `
` 3.2 xx 10 ^(-5) M`
` 3. 6 xx 10 ^(-5) ` M

SOLUTION :`POH =P^(K_b)+ log ""( [S])/([B]) `
If ` [S] =[B] rArr pOH = P^(K_b) rArr [OH^(-) ] =K_b`


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