InterviewSolution
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InterviewSolution
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A solution containing `1 mol` per litre of each `Cu(NO_(3))_(2), AgNO_(3),` and` Hg_(2)(NO_(3))_(2)` is being electrolyzed by using inert electrodes. The values of standard electrode potentials in volts `(` reduction potential `)` are `Ag|Ag^(o+)=+0.80, 2Hg|Hg_(2)^(2+)=+0.79` `Cu|Cu^(2+)=+0.34,Mg|Mg^(2+)=-2.37`. With increasing voltage, the sequence of deposition of metals at the cathode will beA. `Ag,Hg,Cu,Mg`B. `Mg,Cu,Hg,Ag`C. `Ag,Hg,Cu,Mg`D. `Cu,Hg,Ag,Mg` |
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Answer» Correct Answer - a Higher the oxidation potential, more easily it is oxidized and faster is the deposition of metal. Decreasing order of `E^(c-)._(o x I dation)` is `:` `E^(c-)._(Ag|Ag^(o+)(0.80))gtE^(c-)._(2Hg|Hg_(2)^(2+))(0.79)gtE^(c-)._(Cu|Cu^(2+)(0.34))gtE^(c-)._(Mg|Mg^(2+)(-2.37))` Hence, the sequence of deposition of metals at the cathode will `Ag, Hg, ` and `Cu`... |
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