1.

A solution contains 20 g of sodium chloride in 95 cm^(3) solution. The density of solution is 1.25 "g cm"^(-3). What is the mass percent of NaCl ?

Answer»


Solution :Density of NACL solution `= 1.25 "G cm"^(-3)` , Volume of solution `= 95 cm^(3)`
MASS of solution = volume `xx` density `= ("95 cm"^(3))xx("1.25 g cm"^(-3))=118.75`g
Mass PERCENT of NaCl `= ("Mass of NaCl")/("Mass of solution")xx100`
`=((20g))/((118.75g))xx100=16.84%`.


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