InterviewSolution
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InterviewSolution
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A solution contains `A^(+)` and `B^(+)` in such a concentration that both deposit simultaneously. If current of `9.65` amp was passed through `100ml` solution for 55 seconds then find the final concentration of `A^(+)` ion if initial concentration of `B^(+)` is `0.1M`. [Fill your answer by multiplying it wity `10^(3)]`. Given: `{:(A^(+)+e^(-)rarrA,,E^(@) =- 0.5 "volt"),(B^(+)+e^(-)rarrB,,E^(@) =- 0.56 "volt"),((2.303RT)/(F) =0.06,,):}` |
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Answer» Correct Answer - 5 `-0.5 -(0.06)/(1)log.(1)/([A^(+)]) =- 0.56 -(0.06)/(1)log.(1)/([B^(+)])` `0.06 = (0.06)/(1)log.([B^(+)])/([A^(+)])` `([B^(+)])/([A^(+)]) = 10` `[A^(+)]_("final") = 0.01` Total equivalent of charge `= (9.65 xx 55)/(96500) = 5.5` meq Final `[A^(+)] = (0.5)/(100) = 0.005` |
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