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A solution contains `Fe^(2+),Fe^(3+) and I^(-)` ions. This solution was treated with iodine at `35^(@)C. E^(@)` for `Fe^(3+)//Fe^(2+)` is +0.77V and `E^(@)` for `I_(2)//2I^(-)=0.536V`. The favourable redox reaction isA. `I^(-)` will oxidised to `I_(2)`B. `Fe^(2+)` will be oxidised to `Fe^(3+)`C. `I_(2)` will be reduced to `I^(-)`D. There will be no redox reaction |
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Answer» Correct Answer - A `2(e^(-)+Fe^(+3)toFe^(+2)" "E^(@)=0.77V` `underline(2I^(-)toI_(2)+2e^(-)" "E^(@)=0.536V" ")` `2Fe^(+3)+2e^(-)to2Fe^(+2)+I_(2)" "E^(o)=E_(o x)^(o)+E_(red)^(o)` `=0.77=0.536=0.164V` So, Reaction will taken place. |
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