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A solution contains mixture of H_(2)SO_(4), H_(2)C_(2)O_420 ml of this solution requires 40 ml of M/10NaOH for neutralization and 20 ml of N/10 KMnO_4 for oxidation. The molarity of H_2C_2O_4, H_2SO_4 are |
Answer» <html><body><p>` <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>.<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>, 0.1`<br/>`0.1, 0. <a href="https://interviewquestions.tuteehub.com/tag/05-256274" style="font-weight:bold;" target="_blank" title="Click to know more about 05">05</a>` <br/>` 0.05, 0.1`<br/>` 0.05, 0.05`</p>Solution :Let molarity of `H_(2)SO_(4)= M_1 and H_2C_2O_4=M_2` <br/> No. of milli equivalents of `(H_2SO_4+H_2C_2O_4)` = No. of milli <a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> of NaOH <br/> `20(2M_1+2M_2)=40xx1/10` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>(M_1+M_2)=4` <br/> `M_1+M_2=0.1 ""...(1)` <br/> No.of milli equivalents of `H_(2)C_(2)O_(4)=` No. of mili equivalents `KMnO_4` <br/> `20(2M_2)=20 xx1/10` <br/> `M_(2) =1/20 =0.05 M...(2)` <br/> `M_1 =0.1 -0.05 =0.05M`</body></html> | |