A solution cotaning 0.10 M in Ba(NO_(3))_(2) and 0.10 M in Sr(NO_(3))_(2). If solid Na_(2)CrO_(4) is added to the solution, what is [Ba^(2+)], when SrCrO_(4) beings to precipitate? [K_(sp)(BaCrO_(4)) = 1.2 xx 10^(-10), K_(sp) (SrCrO_(4)) = 3.5 xx 10^(-5)]

A solution cotaning 0.10 M in Ba(NO_(3))_(2) and 0.10 M in Sr(NO_(3))_

1.	A solution cotaning 0.10 M in Ba(NO_(3))_(2) and 0.10 M in Sr(NO_(3))_(2). If solid Na_(2)CrO_(4) is added to the solution, what is [Ba^(2+)], when SrCrO_(4) beings to precipitate? [K_(sp)(BaCrO_(4)) = 1.2 xx 10^(-10), K_(sp) (SrCrO_(4)) = 3.5 xx 10^(-5)]
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>.4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-7)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.0 xx 10^(-7)`<br/>`6.1 xx 10^(-7)`<br/>`3.4 xx 10^(-7)`</p>Solution :`K_(<a href="https://interviewquestions.tuteehub.com/tag/sp-1219706" style="font-weight:bold;" target="_blank" title="Click to know more about SP">SP</a>)(SrCrO_(4)) = [Sr^(2+)][CrO_(4)^(2-)]` <br/> `[CrO_(4)^(2-)] = (3.5 xx 10^(-5))/(0.1)= 3.5 xx 10^(-4)` <br/> `K_(sp)(BaCrO_(4)) = [Ba^(2)][CrO_(4)^(2-)]` <br/> `[CrO_(4)^(2-)]_("total") = [CrO_(4)^(2-)]` from `SrCrO_(4)` <br/> `[Ba^(2+)] = (1.2 xx 10^(-10))/(3.5 xx 10^(-4)) = 3.4 xx 10^(-7)`</body></html>