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A solution has been prepared by dissolved 60 g of methyl alcohol in 120 g of water. What is the mole fraction of methyl alcohol and water ? |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of `CH_(3)OH=("Mass of "CH_(3)OH)/("<a href="https://interviewquestions.tuteehub.com/tag/molar-562965" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAR">MOLAR</a> mass")=((60 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)/("<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a> g mol"^(-1)))=1.875` mol <br/> Moles of water `= ("Mass of water")/("Molar mass")=((120g)/("18 g mol"^(-1)))=6.667` mol <br/> Mole fraction of `CH_(3)OH=(("1.875 mol"))/(("1.875 mol +6.667 mol"))=(("1.875 mol"))/(("8.542 mol"))=0.220` <br/> Mole fraction water `= 1 - 0.220 = 0.780`.</body></html> | |